2p^2+10p-72=0

Solution for 2p^2+10p-72=0 equation:

2p^2+10p-72=0

a = 2; b = 10; c = -72;
Δ = b2-4ac
Δ = 102-4·2·(-72)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-26}{2*2}=\frac{-36}{4}
=-9
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+26}{2*2}=\frac{16}{4}
=4
$